在树(如二叉树)中,LCA(Lowest Common Ancestor)指的是两个节点的最近公共祖先节点。以下是一个二叉树中寻找LCA的Java代码示例:
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| class TreeNode { int val; TreeNode left; TreeNode right;
TreeNode(int val) { this.val = val; this.left = null; this.right = null; } }
public class LowestCommonAncestor {
public static TreeNode findLCA(TreeNode root, TreeNode node1, TreeNode node2) { if (root == null || root == node1 || root == node2) { return root; }
TreeNode leftLCA = findLCA(root.left, node1, node2); TreeNode rightLCA = findLCA(root.right, node1, node2);
if (leftLCA != null && rightLCA != null) { return root; }
return (leftLCA != null) ? leftLCA : rightLCA; }
public static void main(String[] args) { TreeNode root = new TreeNode(3); root.left = new TreeNode(5); root.right = new TreeNode(1); root.left.left = new TreeNode(6); root.left.right = new TreeNode(2); root.right.left = new TreeNode(0); root.right.right = new TreeNode(8); root.left.right.left = new TreeNode(7); root.left.right.right = new TreeNode(4);
TreeNode node1 = root.left; TreeNode node2 = root.right; TreeNode lca = findLCA(root, node1, node2);
System.out.println("Lowest Common Ancestor of " + node1.val + " and " + node2.val + " is: " + lca.val); } }
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在这个示例中,findLCA
方法使用递归的方式在二叉树中寻找两个给定节点的最近公共祖先。它首先检查根节点是否为其中之一,然后递归搜索左子树和右子树,最终找到最近公共祖先。
请注意,这个示例是基于二叉树的LCA算法,实际应用中可能需要根据具体的数据结构和问题进行适当的修改。